• Via Intersections and Symmetric Differences. The diagram

    commutes, i.e. we have an equality of sets

    \[ U\cup V=\webleft (U\mathbin {\triangle }V\webright )\mathbin {\triangle }\webleft (U\cap V\webright ) \]

    for each $U,V\in \mathcal{P}\webleft (X\webright )$.


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