• Via Unions and Intersections. We have[1]
    \[ U\mathbin {\triangle }V = \webleft (U\cup V\webright )\setminus \webleft (U\cap V\webright ) \]

    for each $X\in \text{Obj}\webleft (\mathsf{Sets}\webright )$ and each $U,V\in \mathcal{P}\webleft (X\webright )$.


Footnotes

[1] Illustration:

Noticed something off, or have any comments? Feel free to reach out!


You can also use the contact form below: