Let $R$, $S$, $R_{1}$, and $R_{2}$ be relations from $A$ to $B$, and let $S_{1}$ and $S_{2}$ be relations from $B$ to $C$.

  1. Interaction With Inverses. We have
    \[ \webleft (R\cup S\webright )^{\dagger } = R^{\dagger }\cup S^{\dagger }. \]
  2. Interaction With Composition. We have
    \[ \webleft (S_{1}\mathbin {\diamond }R_{1}\webright ) \cup \webleft (S_{2}\mathbin {\diamond }R_{2}\webright ) \mathrel {\smash {\overset {\scriptscriptstyle \mathrm{poss.}}\neq }}\webleft (S_{1}\cup S_{2}\webright ) \mathbin {\diamond }\webleft (R_{1}\cup R_{2}\webright ). \]

Item 1: Interaction With Inverses
Clear.
Item 2: Interaction With Composition
Unwinding the definitions, we see that:

  1. The condition for $\webleft (S_{1}\mathbin {\diamond }R_{1}\webright )\cup \webleft (S_{2}\mathbin {\diamond }R_{2}\webright )$ is:
    1. There exists some $b\in B$ such that:
      1. $\require{color}{\color[rgb]{0.835294117647059,0.368627450980392,0.000000000000000}{a\sim _{R_{1}}b}}$ and $\require{color}{\color[rgb]{0.000000000000000,0.447058823529412,0.698039215686274}{b\sim _{S_{1}}c}}$;

      or

      1. $\require{color}{\color[rgb]{0.835294117647059,0.368627450980392,0.000000000000000}{a\sim _{R_{2}}b}}$ and $\require{color}{\color[rgb]{0.000000000000000,0.447058823529412,0.698039215686274}{b\sim _{S_{2}}c}}$;
  2. The condition for $\webleft (S_{1}\cup S_{2}\webright )\mathbin {\diamond }\webleft (R_{1}\cup R_{2}\webright )$ is:
    1. There exists some $b\in B$ such that:
      1. $\require{color}{\color[rgb]{0.835294117647059,0.368627450980392,0.000000000000000}{a\sim _{R_{1}}b}}$ or $\require{color}{\color[rgb]{0.835294117647059,0.368627450980392,0.000000000000000}{a\sim _{R_{2}}b}}$;

      and

      1. $\require{color}{\color[rgb]{0.000000000000000,0.447058823529412,0.698039215686274}{b\sim _{S_{1}}c}}$ or $\require{color}{\color[rgb]{0.000000000000000,0.447058823529412,0.698039215686274}{b\sim _{S_{2}}c}}$.

These two conditions may fail to agree (counterexample omitted), and thus the two resulting relations on $A\times C$ may differ.


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