• Interaction With Precomposition I. If $F$ is fully faithful, then the precomposition functor
    \[ F^{*} \colon \mathsf{Fun}\webleft (\mathcal{D},\mathcal{X}\webright ) \to \mathsf{Fun}\webleft (\mathcal{C},\mathcal{X}\webright ) \]

    can fail to be fully faithful.


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