A functor $F\colon \mathcal{C}\to \mathcal{D}$ is essentially surjective1 if it satisfies the following condition:

  • For each $D\in \text{Obj}\webleft (\mathcal{D}\webright )$, there exists some object $A$ of $\mathcal{C}$ such that $F\webleft (A\webright )\cong D$.


1Further Terminology: Also called an eso functor, where the name “eso” comes from essentially surjective on objects.


Noticed something off, or have any comments? Feel free to reach out!


You can also use the contact form below: